Crie esta função, ela fornecerá a diferença de data exata, como ano meses dias
Create function get_Exact_Date_diff(@date smalldatetime,@date2 smalldatetime)
returns varchar(50)
as
begin
declare @date3 smalldatetime
Declare @month int,@year int,@day int
if @date>@date2
begin
set @[email protected]
set @[email protected]
set @[email protected]
end
SELECT @month=datediff (MONTH,@date,@date2)
if dateadd(month,@month,@date) >@date2
begin
set @[email protected]
end
set @day=DATEDIFF(day,dateadd(month,@month,@date),@date2)
set @[email protected]/12
set @[email protected] % 12
return (case when @year=0 then '' when @year=1 then convert(varchar(50),@year ) + ' year ' when @year>1 then convert(varchar(50),@year ) + ' years ' end)
+ (case when @month=0 then '' when @month=1 then convert(varchar(50),@month ) + ' month ' when @month>1 then convert(varchar(50),@month ) + ' months ' end)
+ (case when @day=0 then '' when @day=1 then convert(varchar(50),@day ) + ' day ' when @day>1 then convert(varchar(50),@day ) + ' days ' end)
end
