use test
db.test.insert({a:1})
db.test.insert({a:2, Date2:new Date("01/07/2012")})
db.test.insert({a:3, Date2:new Date("01/08/2012")})
db.test.insert({a:4, Date1:new Date("01/07/2012"), Date2:new Date("01/07/2012")})
db.test.insert({a:5, Date1:new Date("01/07/2012")})
db.test.insert({a:6, Date1:new Date("01/08/2012")})
primeiro subquerydb.test.distinct('a', {...});
segundo subquerydb.test.distinct('a', {...});
(Date1 == null || Date1 <= today) && (Date2 == null || Date2 <= today)
descontrair
Date1 == null && Date2 == null ||
Date1 == null && Date2 <= today ||
Date1 <= today && Date2 == null ||
Date1 <= today && Date2 <= today ||
consulta
db.test.find(
{
$or :
[
{$and: [
{"Date1": {"$exists": false}},
{"Date2": {"$exists": false}}
]},
{$and: [
{"Date1": {"$exists": false}},
{"Date2": {
"$exists": true,
"$lte": new Date("2012-01-07T04:45:52.057Z")}
}
]},
{$and: [
{"Date2": {"$exists": false}},
{"Date1": {
"$exists": true,
"$lte": new Date("2012-01-07T04:45:52.057Z")}
}
]},
{$and: [
{"Date2": {
"$exists": true,
"$lte": new Date("2012-01-07T04:45:52.057Z")}
},
{"Date1": {
"$exists": true,
"$lte": new Date("2012-01-07T04:45:52.057Z")}
}
]}
]
})
>[ 1 ]
isso deve funcionar também (suponha que 'não existe' e 'null' é o mesmo)
db.test.find(
{
$and :
[
{$or: [
{"Date1": null},
{"Date1": { "$lte": new Date("2012-01-07T04:45:52.057Z")} }
]},
{$or: [
{"Date2": null},
{"Date2": { "$lte": new Date("2012-01-07T04:45:52.057Z")} }
]}
]
}
)
