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Obter duração como diferença de carimbo de data/hora para alterações de local repetidas


Crie uma visualização chamada home_to_work:
CREATE VIEW `home_to_work`AS 
    SELECT b.name, NULL AS `home`, b.timestamp AS `work`
    FROM mytable b
    WHERE b.location = 'work'
            AND NOT EXISTS (
                    SELECT 1 FROM mytable m
                    WHERE b.name = m.name AND m.timestamp < b.timestamp
     )
    UNION ALL
    SELECT a.name, a.timestamp AS `home`, b.timestamp AS `work`
    FROM mytable a
    JOIN mytable b
            ON a.name = b.name AND a.location = 'home' AND b.location = 'work'
     AND a.timestamp < b.timestamp
     AND NOT EXISTS (
                    SELECT 1 FROM mytable m
                    WHERE a.name = m.name AND m.timestamp > a.timestamp AND m.timestamp < b.timestamp
     )
    UNION ALL
    SELECT a.name, a.timestamp AS `home`, NULL AS `work`
    FROM mytable a
    WHERE a.location = 'home'
            AND NOT EXISTS (
                    SELECT 1 FROM mytable m
                    WHERE a.name = m.name AND m.timestamp > a.timestamp
     );

e uma visão chamada work_to_home:
CREATE VIEW `work_to_home`AS 
    SELECT b.name, NULL AS `work`, b.timestamp AS `home`
    FROM mytable b
    WHERE b.location = 'home'
        AND NOT EXISTS (
            SELECT 1 FROM mytable m
            WHERE b.name = m.name AND m.timestamp < b.timestamp
     )
    UNION ALL
    SELECT a.name, a.timestamp AS `work`, b.timestamp AS `home`
    FROM mytable a
    JOIN mytable b
        ON a.name = b.name AND a.location = 'work' AND b.location = 'home'
     AND a.timestamp < b.timestamp
     AND NOT EXISTS (
            SELECT 1 FROM mytable m
            WHERE a.name = m.name AND m.timestamp > a.timestamp AND m.timestamp < b.timestamp
     )
    UNION ALL
    SELECT a.name, a.timestamp AS `work`, NULL AS `home`
    FROM mytable a
    WHERE a.location = 'work'
        AND NOT EXISTS (
            SELECT 1 FROM mytable m
            WHERE a.name = m.name AND m.timestamp > a.timestamp
     );

então use esta consulta:
SELECT `name`, location, `from`, `until`, duration
FROM (
    SELECT h2w.`name`, 'work' AS `location`, h2w.work AS `from`, w2h.work AS `until`, TIMESTAMPDIFF(second, h2w.`work`, w2h.`work`) AS `duration`
    FROM home_to_work h2w
    JOIN work_to_home w2h
      ON h2w.name = w2h.name AND h2w.work < w2h.work AND NOT EXISTS (
        SELECT 1 FROM mytable m
        WHERE h2w.name = m.name AND m.location = 'home' AND m.timestamp > h2w.work AND m.timestamp < w2h.work
    )

    UNION ALL

    SELECT w2h.`name`, 'home' AS `location`, w2h.home AS `from`, h2w.home AS `until`, TIMESTAMPDIFF(second, w2h.`home`, h2w.`home`) AS `duration`
    FROM work_to_home w2h
    JOIN home_to_work h2w
      ON w2h.name = h2w.name AND w2h.home < h2w.home AND NOT EXISTS (
        SELECT 1 FROM mytable m
        WHERE w2h.name = m.name AND m.location = 'work' AND m.timestamp > w2h.home AND m.timestamp < h2w.home
    )
) locations
ORDER BY `name`, `from`

Explicação:Eu derivo as transições de casa para o trabalho e trabalho para casa (incluindo nulo inicial para casa/trabalho e casa/trabalho final para nulo) e, em seguida, uno essas transições verificando se elas são consecutivas.

Aqui está um SQL Fiddle .

Editar em resposta ao seu comentário:

Obter a última localização conhecida de uma determinada pessoa e hora é fácil:
SELECT location
FROM mytable
WHERE `name` = 'John' AND timestamp < '2015-07-08 11:07:00'
ORDER BY timestamp DESC
LIMIT 1