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Calcular o total de dias úteis entre duas datas


Se você deseja excluir apenas fins de semana, basta excluí-los usando uma contagem condicional adicionando:
count(distinct case when datepart(weekday, getdate()) <= 5 then date end)

Assim, sua consulta se torna:
set datefirst 1;

select  count(distinct(dateadd(d, 0, datediff(d, 0,checktime)))) as workingdays,
        count(distinct case when datepart(weekday, getdate()) <= 5 
                            then dateadd(d, 0, datediff(d, 0,checktime)) 
                        end) as weekdays
from departments,
 dbo.USERINFO INNER JOIN dbo.CHECKINOUT ON 
     dbo.USERINFO.USERID = dbo.CHECKINOUT.USERID
where  userinfo.name='Gokul Gopalakrishnan' and deptname='GEN/SUP-TBL' 
and checktime>='2014-05-01' and checktime<='2014-05-30'

ENTÃO Eu realmente recomendo adicionar um tabela de calendário ao seu banco de dados. Isso torna tudo tão fácil que sua consulta se tornaria:
SELECT  DaysWorked = COUNT(cio.Date),
        WeekDaysWorked = COUNT(CASE WHEN c.IsWeekDay = 1 THEN cio.Date END),
        WorkingDaysWorked = COUNT(CASE WHEN c.IsWorkingDay = 1 THEN cio.Date END),
        TotalDays = COUNT(*),
        TotalWeekDays = COUNT(CASE WHEN c.IsWeekDay = 1 THEN 1 END),
        TotalWorkingDays = COUNT(CASE WHEN c.IsWorkingDay = 1 THEN 1 END)
FROM    dbo.Calender AS c
        LEFT JOIN
        (   SELECT  DISTINCT
                    Date = CAST(CheckTime AS DATE)
            FROM    dbo.Departments AS d
                    CROSS JOIN dbo.userInfo AS ui
                    INNER JOIN dbo.CheckInOut AS cio
                        ON cio.UserID = ui.UserID
            WHERE   ui.Name = 'Gokul Gopalakrishnan' 
            AND     d.deptname = 'GEN/SUP-TBL' 
        ) AS cio
            ON c.Date = cio.Date
WHERE   d.Date >= '2014-05-01'
AND     d.Date <= '2014-05-30';

Desta forma, você pode definir feriados, fins de semana, etc. É muito mais flexível do que qualquer outra solução.

EDITAR

Acho que não entendi seus critérios originais. Isso deve funcionar para você sem tabela de calendário:
SET DATEFIRST 1;

DECLARE @StartDate DATE = '2014-05-01', 
        @EndDate DATE = '2014-05-30';

DECLARE @Workdays INT = 
    (DATEDIFF(DAY, @StartDate, @EndDate) + 1)
    -(DATEDIFF(WEEK, @StartDate, @EndDate) * 2)
    -(CASE WHEN DATEPART(WEEKDAY, @StartDate) = 7 THEN 1 ELSE 0 END)
    -(CASE WHEN DATEPART(WEEKDAY, @EndDate) = 6 THEN 1 ELSE 0 END);


SELECT  WorkingDays = COUNT(DISTINCT CAST(CheckTime AS DATE)),
        BusinessDays = @Workdays
FROM    dbo.Departments AS d
        CROSS JOIN dbo.userInfo AS ui
        INNER JOIN dbo.CheckInOut AS cio
            ON cio.UserID = ui.UserID
WHERE   ui.Name = 'Gokul Gopalakrishnan' 
AND     d.deptname = 'GEN/SUP-TBL' 
AND     cio.CheckTime >= @StartDate
AND     cio.CheckTime <= @EndDate;