Bom dia,
Por favor, verifique se a solução abaixo resolve todas as suas necessidades. Eu testei com seus dados e com mais algumas linhas, mas é sempre melhor verificar novamente. À primeira vista, parece que retorna o resultado solicitado. vou adicionar uma explicação mais tarde
A consulta que estou usando é esta:
DECLARE @Date DATE = '2018-06-12';
with MyCTE as (
SELECT
t.CustName,t.Country,t.RecordedTime,t.CurrNo, D = CONVERT(DATE, RecordedTime)
,RN_D = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo desc)
,RN = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo)
,RN_Old = ROW_NUMBER()
OVER (partition by t.CustName, (CASE WHEN CONVERT(DATE, RecordedTime) < @Date then 0 else 1 END) order by t.CurrNo desc)
,Cnt = COUNT(*)
OVER (partition by t.CustName)
,CntToday = COUNT(CASE WHEN CONVERT(DATE, RecordedTime) = @Date THEN 1 ELSE NULL END)
OVER (partition by t.CustName)
FROM Test t
where
-- returns rows untill current date
CONVERT (DATE, RecordedTime) <= @Date
-- only if relevnat to current date
and EXISTS (
SELECT * FROM test t0
where CONVERT (DATE, RecordedTime) = @Date and t0.CustName = t.CustName
)
)
,MyCTE2 as (
select
CustName, Country, RecordedTime, D, CurrNo, RN_D, RN, Cnt, t2.c, History, CntToday, RN_Old
from MyCTE t1
left JOIN (select * from (values(1, 'NEW'),(1, 'BEFORE')) t2(c, History) ) t2
on t1.CurrNo = t2.c
and CntToday > 1
and D = @Date
where
RN_D = 1
or (RN = 1 and D = @Date)
or (RN_Old = 1 and D < @Date)
)
,MyCTE3 as (
select CustName, Country, RecordedTime
-- unmarke the bellow comment in order to get the accessories columns I used
-- This is recommended to understand the line-of-thinking
--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
, History = CASE
WHEN CurrNo = 1 and Cnt = 1 then 'NEW'
WHEN RN_D = 1 then 'CURRENT'
else ISNULL(History,'BEFORE')
END
from MyCTE2
)
select CustName, Country, RecordedTime--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
,Audit = CASE when History='New' then 'ADD' else 'CHANGE' END
, History
from MyCTE3
Para simplificar o teste, insiro a consulta inteira na função de tabela
DROP FUNCTION IF EXISTS dbo.F
GO
CREATE FUNCTION dbo.F(@Date DATE)
RETURNS TABLE AS RETURN (
--DECLARE @Date DATE = '2018-06-12';
with MyCTE as (
SELECT
t.CustName,t.Country,t.RecordedTime,t.CurrNo, D = CONVERT(DATE, RecordedTime)
,RN_D = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo desc)
,RN = ROW_NUMBER()
OVER (partition by t.CustName order by t.CurrNo)
,RN_Old = ROW_NUMBER()
OVER (partition by t.CustName, (CASE WHEN CONVERT(DATE, RecordedTime) < @Date then 0 else 1 END) order by t.CurrNo desc)
,Cnt = COUNT(*)
OVER (partition by t.CustName)
,CntToday = COUNT(CASE WHEN CONVERT(DATE, RecordedTime) = @Date THEN 1 ELSE NULL END)
OVER (partition by t.CustName)
FROM Test t
where
-- returns rows untill current date
CONVERT (DATE, RecordedTime) <= @Date
-- only if relevnat to current date
and EXISTS (
SELECT * FROM test t0
where CONVERT (DATE, RecordedTime) = @Date and t0.CustName = t.CustName
)
)
,MyCTE2 as (
select
CustName, Country, RecordedTime, D, CurrNo, RN_D, RN, Cnt, t2.c, History, CntToday, RN_Old
from MyCTE t1
left JOIN (select * from (values(1, 'NEW'),(1, 'BEFORE')) t2(c, History) ) t2
on t1.CurrNo = t2.c
and CntToday > 1
and D = @Date
where
RN_D = 1
or (RN = 1 and D = @Date)
or (RN_Old = 1 and D < @Date)
)
,MyCTE3 as (
select CustName, Country, RecordedTime
-- unmarke the bellow comment in order to get the accessories columns I used
-- This is recommended to understand the line-of-thinking
--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
, History = CASE
WHEN CurrNo = 1 and Cnt = 1 then 'NEW'
WHEN RN_D = 1 then 'CURRENT'
else ISNULL(History,'BEFORE')
END
from MyCTE2
)
select CustName, Country, RecordedTime--, D, c, RN_D, RN, CurrNo, Cnt, CntToday, RN_Old
,Audit = CASE when History='New' then 'ADD' else 'CHANGE' END
, History
from MyCTE3
--order by CustName, RecordedTime
)
GO
Usando a função é mais simples fazer vários testes, mas provavelmente na produção você vai querer usar a consulta direta
-- Test
select * from F('2018-06-01') order by CustName , RecordedTime
select * from F('2018-06-02') order by CustName , RecordedTime
select * from F('2018-06-03') order by CustName , RecordedTime
select * from F('2018-06-10') order by CustName , RecordedTime
select * from F('2018-06-11') order by CustName , RecordedTime
select * from F('2018-06-12') order by CustName , RecordedTime
select * from F('2018-06-13') order by CustName , RecordedTime
select * from F('2018-06-14') order by CustName , RecordedTime
/**************** Atualização em 2018-08-19 14:05 Hora de Israel ****************/
Percebo que é importante adicionar mais algumas informações para participar do tópico. Espero que isso seja útil
Primeiro, vamos comparar a porcentagem de uso de recursos de acordo com os Planos de Execução de três consultas:(1) Minha solução, (2) maulik kansara segundos solução após atualizar a primeira solução e (3) maulik kansara primeira solução
Agora vamos verificar a imagem do EP da solução maulik kansara segundos:
Esta consulta verifica a tabela 11 vezes!
