Se você não tiver uma tabela com todas as datas entre a data de início e a data de término (inclusive), precisará adotar uma consulta que criará primeiro todas as datas entre o intervalo de datas fornecido (inclusive). Em seguida, use
WEEKDAY função de MySQL para verificar se o dia é Saturday ou Sunday SELECT
dateTable.Day,
DAYNAME(dateTable.Day) AS dayName
FROM
( SELECT ADDDATE('2016-07-01', INTERVAL @i:[email protected]+1 DAY) AS DAY
FROM (
SELECT a.a
FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
) a
JOIN (SELECT @i := -1) r1
WHERE
@i < DATEDIFF('2016-08-01', '2016-07-01')
) AS dateTable
WHERE WEEKDAY(dateTable.Day) IN (5,6)
ORDER BY dateTable.Day;
DEMONSTRAÇÃO DE TRABALHO
Observação:
WEEKDAY
retorna o índice do dia da semana para a data (0 =segunda-feira, 1 =terça-feira, … 6 =domingo). EDITAR:
Se você precisar apenas de
count :SELECT
COUNT(*) AS total
FROM
( SELECT ADDDATE('2016-07-01', INTERVAL @i:[email protected]+1 DAY) AS DAY
FROM (
SELECT a.a
FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
) a
JOIN (SELECT @i := -1) r1
WHERE
@i < DATEDIFF('2016-08-01', '2016-07-01')
) AS dateTable
WHERE WEEKDAY(dateTable.Day) IN (5,6)
Demonstração
