Primeiro, reescreva sua consulta. Use visualizações ou expressão de tabela comum para evitar repetir três vezes para seu
SELECT
, GROUP BY
, ORDER BY
cláusulas. Sua consulta se torna:WITH data AS (
SELECT(CASE WHEN time_dtm > SYSDATE -1 THEN '0-1 day'
WHEN time_dtm > SYSDATE -2 AND
time_dtm < SYSDATE -1 THEN '1-2 days'
WHEN time_dtm > SYSDATE -3 AND
time_dtm < SYSDATE -2 THEN '2-3 days'
WHEN time_dtm > SYSDATE -4 AND
time_dtm < SYSDATE -3 THEN '3-4 days'
WHEN time_dtm > SYSDATE -5 AND
time_dtm < SYSDATE -4 THEN 'Closed'
END) AS Age
FROM table_1
WHERE id IN (1,2,3)
)
SELECT Age, COUNT(*)
FROM data
GROUP BY Age
ORDER BY Age
Então, para ter certeza de que qualquer um dos grupos desejados estará disponível no resultado, você tem muitas opções.
Você pode usar UNION ALL
:
WITH data AS (
SELECT(CASE WHEN time_dtm > SYSDATE -1 THEN '0-1 day'
WHEN time_dtm > SYSDATE -2 AND
time_dtm < SYSDATE -1 THEN '1-2 days'
WHEN time_dtm > SYSDATE -3 AND
time_dtm < SYSDATE -2 THEN '2-3 days'
WHEN time_dtm > SYSDATE -4 AND
time_dtm < SYSDATE -3 THEN '3-4 days'
WHEN time_dtm > SYSDATE -5 AND
time_dtm < SYSDATE -4 THEN 'Closed'
END) AS Age
FROM table_1
WHERE id IN (1,2,3)
-- The below will add one record for every desired Age group
UNION ALL
SELECT '0-1 day' FROM DUAL UNION ALL
SELECT '1-2 days' FROM DUAL UNION ALL
SELECT '2-3 days' FROM DUAL UNION ALL
SELECT '3-4 days' FROM DUAL UNION ALL
SELECT 'Closed' FROM DUAL
)
SELECT Age, COUNT(*) - 1 -- Subtract the extra record again
FROM data
GROUP BY Age
ORDER BY Age
Uma solução totalmente diferente envolveria LEFT OUTER JOINs
:
-- Groups is a dynamic table that contains the date ranges and their "Age" label
WITH groups AS (
SELECT SYSDATE -1 lower, SYSDATE upper, '0-1 day' Age FROM DUAL UNION ALL
SELECT SYSDATE -2 , SYSDATE -1 , '1-2 days' FROM DUAL UNION ALL
SELECT SYSDATE -3 , SYSDATE -2 , '2-3 days' FROM DUAL UNION ALL
SELECT SYSDATE -4 , SYSDATE -3 , '3-4 days' FROM DUAL UNION ALL
SELECT SYSDATE -5 , SYSDATE -4 , 'Closed' FROM DUAL
)
SELECT g.Age, NVL(SUM(t.counter), 0)
FROM groups g
-- LEFT OUTER JOINing "table_1" to "groups" will ensure that every group
-- appears at least once in the result
LEFT OUTER JOIN (
SELECT 1 counter, t.* FROM table_1 t WHERE t.id IN (1,2,3)
) t
ON t.time_dtm >= g.lower
AND t.time_dtm < g.upper
GROUP BY g.Age
ORDER BY g.Age
No segundo exemplo, você também pode ficar sem um CTE e usar um SELECT aninhado para os
groups
tabela. É fácil ver como o segundo exemplo é mais simples de evoluir no futuro, caso seus requisitos mudem.