Transformação de tabela / análise de campo em PL/SQL

SQL> select id
  2       , value
  3    from codes
  4   model
  5         return updated rows
  6         partition by (id)
  7         dimension by (-1 i)
  8         measures (value)
  9         ( value[for i from 0 to length(value[-1])-length(replace(value[-1],',')) increment 1]
 10           = regexp_substr(value[-1],'[^,]+',1,cv(i)+1)
 11         )
 12   order by id
 13       , i
 14  /

        ID VALUE
---------- -------------------
        10 A
        10 B
        10 C
        11 A
        11 B
        12 A
        12 B
        12 C
        12 D
        12 E
        12 F
        13 R
        13 T
        13 D
        13 W
        13 W
        13 W
        13 W
        13 W
        13 S
        13 S

21 rows selected.