Você precisa primeiro percorrer a árvore para obter todos os gerentes e depois descer para buscar todos os funcionários:
select level, employee_id, last_name, manager_id ,
connect_by_root employee_id as root_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 101
)
;
Consulte http://www.sqlfiddle.com/#!4/d15e7/18
Editar:
Se o nó fornecido também for o nó raiz, estenda a consulta para incluir o nó fornecido na lista de nós pais:
Exemplo para nó não raiz:
select distinct employee_id, last_name, manager_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 101
union
select manager_id -- in case we are the root node
from employees
where manager_id = 101
)
;
Exemplo para nó raiz:
select distinct employee_id, last_name, manager_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 100
union
select manager_id -- in case we are the root node
from employees
where manager_id = 100
)
;
Mexa em http://www.sqlfiddle.com/#!4/d15e7/32
